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d = (X2 + Y2)1/2 Computing this function requires a square root, which even on modern computers is expensive. It is solved by iterative approximation - which means thecomputer enters a loop approximating the square root until it is within a given error margin. If you are working on more limited hardware which does nothave a square root function implemented in hardware, then computing even a small number of square roots may be prohibitive. Phototangler 2.1 SystemFor many computations it is possible to compare square distances and so to avoid doing square roots at all. For example, if your computation isconcerned only with comparing distances, then comparing square distances is equivalent. However, there are computations where you really do need to getdistances - say if you need to normalize vectors, or you are implementing a collision system using spherical bounding volumes.In these cases, if you cannot afford to compute the standard distance function, there are classes of functions which give a pretty good approximationto the distance function and which are composed entirely of easy to compute linear pieces. In theory you can keep making a linear approximation of anon-linear function arbitrarily accurate by adding more pieces. In fact this is not unlike what the square root function does when implemented oncomputers. The functions I will be discussing can generally approximate the distance within2.5% average error, and with about a 5% maximum error with a small number of linear components and are therefore very fast to run. They can be adjusted totrade off maximum error for average error and you can construct functions that will move the error to certain places. First lets look at a 3d plot of the true distance function. This 3d patch represents a euclidean distance function where x and y range from -1 to 1.The height of the plot represents the negative distance. So when x and y are equal to zero, the distance is equal to zero, and that is the peak of thecone. Increasing values of x and y correspond to points lower down on the cone. The cross section of this plot would look like a circle. Here are plots of the maximum and minimum of the absolute value of x and y, where x and y range from -1 to 1. The maximum plot is a 4 sided pyramid.The point where x and y are equal to zero corresponds to the top of the pyramid. Its cross section is a square. You can see that the plot for the minimumtends to operate as an inverse of the pyramid. Its cross section looks like a cross. Therefore if you make a linear combination of these two functions you get a pretty good approximation to the distance function.Different scaling values formin and max will give you approximations with different properties. This one is balanced to produce the smallest possible maximum error. You can alsobalance the function to produce a minimum average error, or minimum average square error. You can see that the places of maximum error are where eitherx or y approach zero. That is, these are the places where the shape of the cross section tends to deviate most fromthe ideal circle. ( It is possible to reduce the error at these points to zero by adjusting the scaling factors, but at great cost to accuracyeverywhere else ). You can improve the accuracy of this function by adding a term specifically designed to correct error at these points. In this case we change the scalingof this function only where the larger of x or y, is greater than 16 times the value of the smaller of x or y. You can see in the plot of this new functionthat the sharp indentations where x or y approach zero are somewhat rounded out. You can continue to process further reducing the amount of erroruntil it is suitably accurate for your purposes. Of course as you add linear pieces to the function it becomes more expensive to compute.
It is easy to demonstrate that for any approximate distance function that you want to work with the minimum and maximums of the absolute valuesof x and y. Consider that for the true distance function, for any given distance X you get points on a circle with radius X. So you are essentiallytrying to make an approximation of a circular graph using straight lines. Notice that taking the absolute value of x and y does not change the result ofthe distance function. Nor does swapping x and y. Simple image 6 3 12. By first taking the absolute values of x and y, you are reducing the problem to approximating onlyone quadrant of the circle. By further considering the mininum and maximum of x and y you are constraining the problem to just one octant of a circle.This is a small enough arc that you can get a pretty good approximation with just a few straight lines.
These functions are very easy to compute, and they can be computed on modern hardware in constant time. Notice that the coefficients I am usingare expressed as fractions of 1024. This means that you can implement this function without using only integer registers and a few multiplies and thenfinally scale the result down by shifting. Expressing your coefficients using a denominator that is a power of two will let you do this. How many bits youuse will depend on the size of your registers and how much accuracy you need. Here is an example implementation of one of the given approximation functions:
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Phototangler 2.1 DownloadIt is also possible to implement this approximation without even using multiplies if your hardware is that limited: Phototangler 2.1 InchPhotoTangler Collage Maker v1.3 APK DownloadPhotoTangler Collage Maker v1.3 APKPhototangler 2.1 Answers
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